4(y+1)+y=8(y-1)=+6

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Solution for 4(y+1)+y=8(y-1)=+6 equation: 



4(y+1)+y=8(y-1)=+6

We move all terms to the left:

4(y+1)+y-(8(y-1))=0

We add all the numbers together, and all the variables

y+4(y+1)-(8(y-1))=0

We multiply parentheses

y+4y-(8(y-1))+4=0



We calculate terms in parentheses: -(8(y-1)), so:

8(y-1)

We multiply parentheses

8y-8

Back to the equation:

-(8y-8)



We add all the numbers together, and all the variables

5y-(8y-8)+4=0

We get rid of parentheses

5y-8y+8+4=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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