4(y+1)-3(y-5)=3(y-1)

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Solution for 4(y+1)-3(y-5)=3(y-1) equation:



4(y+1)-3(y-5)=3(y-1)
We move all terms to the left:
4(y+1)-3(y-5)-(3(y-1))=0
We multiply parentheses
4y-3y-(3(y-1))+4+15=0
We calculate terms in parentheses: -(3(y-1)), so:
3(y-1)
We multiply parentheses
3y-3
Back to the equation:
-(3y-3)
We add all the numbers together, and all the variables
y-(3y-3)+19=0
We get rid of parentheses
y-3y+3+19=0
We add all the numbers together, and all the variables
-2y+22=0
We move all terms containing y to the left, all other terms to the right
-2y=-22
y=-22/-2
y=+11

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