4(y+1)-3(y-5)=3(y-1)

Solution for 4(y+1)-3(y-5)=3(y-1) equation:

4(y+1)-3(y-5)=3(y-1)

We move all terms to the left:

4(y+1)-3(y-5)-(3(y-1))=0

We multiply parentheses

4y-3y-(3(y-1))+4+15=0


We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)


We add all the numbers together, and all the variables

y-(3y-3)+19=0

We get rid of parentheses

y-3y+3+19=0

We add all the numbers together, and all the variables

-2y+22=0

We move all terms containing y to the left, all other terms to the right

-2y=-22

y=-22/-2

y=+11