4(y+1)-7=3(y-1)+4

Solution for 4(y+1)-7=3(y-1)+4 equation:

4(y+1)-7=3(y-1)+4

We move all terms to the left:

4(y+1)-7-(3(y-1)+4)=0

We multiply parentheses

4y-(3(y-1)+4)+4-7=0


We calculate terms in parentheses: -(3(y-1)+4), so:

3(y-1)+4

We multiply parentheses

3y-3+4

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)


We add all the numbers together, and all the variables

4y-(3y+1)-3=0

We get rid of parentheses

4y-3y-1-3=0

We add all the numbers together, and all the variables

y-4=0

We move all terms containing y to the left, all other terms to the right

y=4