4(y+1)-7=3(y-1)+7

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Solution for 4(y+1)-7=3(y-1)+7 equation: 



4(y+1)-7=3(y-1)+7

We move all terms to the left:

4(y+1)-7-(3(y-1)+7)=0

We multiply parentheses

4y-(3(y-1)+7)+4-7=0



We calculate terms in parentheses: -(3(y-1)+7), so:

3(y-1)+7

We multiply parentheses

3y-3+7

We add all the numbers together, and all the variables

3y+4

Back to the equation:

-(3y+4)



We add all the numbers together, and all the variables

4y-(3y+4)-3=0

We get rid of parentheses

4y-3y-4-3=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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