4(y+1)-7=3(y-1)+y

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Solution for 4(y+1)-7=3(y-1)+y equation:


Simplifying
4(y + 1) + -7 = 3(y + -1) + y

Reorder the terms:
4(1 + y) + -7 = 3(y + -1) + y
(1 * 4 + y * 4) + -7 = 3(y + -1) + y
(4 + 4y) + -7 = 3(y + -1) + y

Reorder the terms:
4 + -7 + 4y = 3(y + -1) + y

Combine like terms: 4 + -7 = -3
-3 + 4y = 3(y + -1) + y

Reorder the terms:
-3 + 4y = 3(-1 + y) + y
-3 + 4y = (-1 * 3 + y * 3) + y
-3 + 4y = (-3 + 3y) + y

Combine like terms: 3y + y = 4y
-3 + 4y = -3 + 4y

Add '3' to each side of the equation.
-3 + 3 + 4y = -3 + 3 + 4y

Combine like terms: -3 + 3 = 0
0 + 4y = -3 + 3 + 4y
4y = -3 + 3 + 4y

Combine like terms: -3 + 3 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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