4(y+1)-7=3y-3+y

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Solution for 4(y+1)-7=3y-3+y equation: 



4(y+1)-7=3y-3+y

We move all terms to the left:

4(y+1)-7-(3y-3+y)=0

We add all the numbers together, and all the variables

4(y+1)-(4y-3)-7=0

We multiply parentheses

4y-(4y-3)+4-7=0

We get rid of parentheses

4y-4y+3+4-7=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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