4(y+1)-y=3(y+1)+3

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Solution for 4(y+1)-y=3(y+1)+3 equation: 


Simplifying
4(y + 1) + -1y = 3(y + 1) + 3

Reorder the terms:
4(1 + y) + -1y = 3(y + 1) + 3
(1 * 4 + y * 4) + -1y = 3(y + 1) + 3
(4 + 4y) + -1y = 3(y + 1) + 3

Combine like terms: 4y + -1y = 3y
4 + 3y = 3(y + 1) + 3

Reorder the terms:
4 + 3y = 3(1 + y) + 3
4 + 3y = (1 * 3 + y * 3) + 3
4 + 3y = (3 + 3y) + 3

Reorder the terms:
4 + 3y = 3 + 3 + 3y

Combine like terms: 3 + 3 = 6
4 + 3y = 6 + 3y

Add '-3y' to each side of the equation.
4 + 3y + -3y = 6 + 3y + -3y

Combine like terms: 3y + -3y = 0
4 + 0 = 6 + 3y + -3y
4 = 6 + 3y + -3y

Combine like terms: 3y + -3y = 0
4 = 6 + 0
4 = 6

Solving
4 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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