4(y+1)-y=3(y-1)+7

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Solution for 4(y+1)-y=3(y-1)+7 equation: 


Simplifying
4(y + 1) + -1y = 3(y + -1) + 7

Reorder the terms:
4(1 + y) + -1y = 3(y + -1) + 7
(1 * 4 + y * 4) + -1y = 3(y + -1) + 7
(4 + 4y) + -1y = 3(y + -1) + 7

Combine like terms: 4y + -1y = 3y
4 + 3y = 3(y + -1) + 7

Reorder the terms:
4 + 3y = 3(-1 + y) + 7
4 + 3y = (-1 * 3 + y * 3) + 7
4 + 3y = (-3 + 3y) + 7

Reorder the terms:
4 + 3y = -3 + 7 + 3y

Combine like terms: -3 + 7 = 4
4 + 3y = 4 + 3y

Add '-4' to each side of the equation.
4 + -4 + 3y = 4 + -4 + 3y

Combine like terms: 4 + -4 = 0
0 + 3y = 4 + -4 + 3y
3y = 4 + -4 + 3y

Combine like terms: 4 + -4 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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