4(y+1)-y=3(y-1)=3

Solution for 4(y+1)-y=3(y-1)=3 equation:

4(y+1)-y=3(y-1)=3

We move all terms to the left:

4(y+1)-y-(3(y-1))=0

We add all the numbers together, and all the variables

-1y+4(y+1)-(3(y-1))=0

We multiply parentheses

-1y+4y-(3(y-1))+4=0


We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)


We add all the numbers together, and all the variables

3y-(3y-3)+4=0

We get rid of parentheses

3y-3y+3+4=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation