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4(y+1)-y=3(y-2)+2
We move all terms to the left:
4(y+1)-y-(3(y-2)+2)=0
We add all the numbers together, and all the variables
-1y+4(y+1)-(3(y-2)+2)=0
We multiply parentheses
-1y+4y-(3(y-2)+2)+4=0
We calculate terms in parentheses: -(3(y-2)+2), so:We add all the numbers together, and all the variables
3(y-2)+2
We multiply parentheses
3y-6+2
We add all the numbers together, and all the variables
3y-4
Back to the equation:
-(3y-4)
3y-(3y-4)+4=0
We get rid of parentheses
3y-3y+4+4=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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