4(y+1)-y=3(y-2)+2

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Solution for 4(y+1)-y=3(y-2)+2 equation: 



4(y+1)-y=3(y-2)+2

We move all terms to the left:

4(y+1)-y-(3(y-2)+2)=0

We add all the numbers together, and all the variables

-1y+4(y+1)-(3(y-2)+2)=0

We multiply parentheses

-1y+4y-(3(y-2)+2)+4=0



We calculate terms in parentheses: -(3(y-2)+2), so:

3(y-2)+2

We multiply parentheses

3y-6+2

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)



We add all the numbers together, and all the variables

3y-(3y-4)+4=0

We get rid of parentheses

3y-3y+4+4=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation

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