4(y+1)=12

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Solution for 4(y+1)=12 equation: 



4(y+1)=12

We move all terms to the left:

4(y+1)-(12)=0

We multiply parentheses

4y+4-12=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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