4(y+1)=2(1-2y)-6

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Solution for 4(y+1)=2(1-2y)-6 equation: 



4(y+1)=2(1-2y)-6

We move all terms to the left:

4(y+1)-(2(1-2y)-6)=0

We add all the numbers together, and all the variables

4(y+1)-(2(-2y+1)-6)=0

We multiply parentheses

4y-(2(-2y+1)-6)+4=0



We calculate terms in parentheses: -(2(-2y+1)-6), so:

2(-2y+1)-6

We multiply parentheses

-4y+2-6

We add all the numbers together, and all the variables

-4y-4

Back to the equation:

-(-4y-4)



We get rid of parentheses

4y+4y+4+4=0

We add all the numbers together, and all the variables

8y+8=0

We move all terms containing y to the left, all other terms to the right

8y=-8

y=-8/8

y=-1

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