4(y+1)=2(y-13)

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Solution for 4(y+1)=2(y-13) equation: 



4(y+1)=2(y-13)

We move all terms to the left:

4(y+1)-(2(y-13))=0

We multiply parentheses

4y-(2(y-13))+4=0



We calculate terms in parentheses: -(2(y-13)), so:

2(y-13)

We multiply parentheses

2y-26

Back to the equation:

-(2y-26)



We get rid of parentheses

4y-2y+26+4=0

We add all the numbers together, and all the variables

2y+30=0

We move all terms containing y to the left, all other terms to the right

2y=-30

y=-30/2

y=-15

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