4(y+1)=2y+3+2y

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Solution for 4(y+1)=2y+3+2y equation:


Simplifying
4(y + 1) = 2y + 3 + 2y

Reorder the terms:
4(1 + y) = 2y + 3 + 2y
(1 * 4 + y * 4) = 2y + 3 + 2y
(4 + 4y) = 2y + 3 + 2y

Reorder the terms:
4 + 4y = 3 + 2y + 2y

Combine like terms: 2y + 2y = 4y
4 + 4y = 3 + 4y

Add '-4y' to each side of the equation.
4 + 4y + -4y = 3 + 4y + -4y

Combine like terms: 4y + -4y = 0
4 + 0 = 3 + 4y + -4y
4 = 3 + 4y + -4y

Combine like terms: 4y + -4y = 0
4 = 3 + 0
4 = 3

Solving
4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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