4(y+1)=3y+7

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Solution for 4(y+1)=3y+7 equation: 



4(y+1)=3y+7

We move all terms to the left:

4(y+1)-(3y+7)=0

We multiply parentheses

4y-(3y+7)+4=0

We get rid of parentheses

4y-3y-7+4=0

We add all the numbers together, and all the variables

y-3=0

We move all terms containing y to the left, all other terms to the right

y=3

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