4(y+1)=5(y-1)+12

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Solution for 4(y+1)=5(y-1)+12 equation: 


Simplifying
4(y + 1) = 5(y + -1) + 12

Reorder the terms:
4(1 + y) = 5(y + -1) + 12
(1 * 4 + y * 4) = 5(y + -1) + 12
(4 + 4y) = 5(y + -1) + 12

Reorder the terms:
4 + 4y = 5(-1 + y) + 12
4 + 4y = (-1 * 5 + y * 5) + 12
4 + 4y = (-5 + 5y) + 12

Reorder the terms:
4 + 4y = -5 + 12 + 5y

Combine like terms: -5 + 12 = 7
4 + 4y = 7 + 5y

Solving
4 + 4y = 7 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
4 + 4y + -5y = 7 + 5y + -5y

Combine like terms: 4y + -5y = -1y
4 + -1y = 7 + 5y + -5y

Combine like terms: 5y + -5y = 0
4 + -1y = 7 + 0
4 + -1y = 7

Add '-4' to each side of the equation.
4 + -4 + -1y = 7 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = 7 + -4
-1y = 7 + -4

Combine like terms: 7 + -4 = 3
-1y = 3

Divide each side by '-1'.
y = -3

Simplifying
y = -3

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