4(y+1)=6y+2

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Solution for 4(y+1)=6y+2 equation: 



4(y+1)=6y+2

We move all terms to the left:

4(y+1)-(6y+2)=0

We multiply parentheses

4y-(6y+2)+4=0

We get rid of parentheses

4y-6y-2+4=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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