4(y+1)=7(y-2)

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Solution for 4(y+1)=7(y-2) equation:


Simplifying
4(y + 1) = 7(y + -2)

Reorder the terms:
4(1 + y) = 7(y + -2)
(1 * 4 + y * 4) = 7(y + -2)
(4 + 4y) = 7(y + -2)

Reorder the terms:
4 + 4y = 7(-2 + y)
4 + 4y = (-2 * 7 + y * 7)
4 + 4y = (-14 + 7y)

Solving
4 + 4y = -14 + 7y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7y' to each side of the equation.
4 + 4y + -7y = -14 + 7y + -7y

Combine like terms: 4y + -7y = -3y
4 + -3y = -14 + 7y + -7y

Combine like terms: 7y + -7y = 0
4 + -3y = -14 + 0
4 + -3y = -14

Add '-4' to each side of the equation.
4 + -4 + -3y = -14 + -4

Combine like terms: 4 + -4 = 0
0 + -3y = -14 + -4
-3y = -14 + -4

Combine like terms: -14 + -4 = -18
-3y = -18

Divide each side by '-3'.
y = 6

Simplifying
y = 6

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