4(y+12)=48

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Solution for 4(y+12)=48 equation: 



4(y+12)=48

We move all terms to the left:

4(y+12)-(48)=0

We multiply parentheses

4y+48-48=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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