4(y+2)+3=11+4y

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Solution for 4(y+2)+3=11+4y equation: 



4(y+2)+3=11+4y

We move all terms to the left:

4(y+2)+3-(11+4y)=0

We add all the numbers together, and all the variables

4(y+2)-(4y+11)+3=0

We multiply parentheses

4y-(4y+11)+8+3=0

We get rid of parentheses

4y-4y-11+8+3=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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