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4(y+2)+3y=2(y+1)+1
We move all terms to the left:
4(y+2)+3y-(2(y+1)+1)=0
We add all the numbers together, and all the variables
3y+4(y+2)-(2(y+1)+1)=0
We multiply parentheses
3y+4y-(2(y+1)+1)+8=0
We calculate terms in parentheses: -(2(y+1)+1), so:We add all the numbers together, and all the variables
2(y+1)+1
We multiply parentheses
2y+2+1
We add all the numbers together, and all the variables
2y+3
Back to the equation:
-(2y+3)
7y-(2y+3)+8=0
We get rid of parentheses
7y-2y-3+8=0
We add all the numbers together, and all the variables
5y+5=0
We move all terms containing y to the left, all other terms to the right
5y=-5
y=-5/5
y=-1
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