4(y+2)+3y=36

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Solution for 4(y+2)+3y=36 equation: 



4(y+2)+3y=36

We move all terms to the left:

4(y+2)+3y-(36)=0

We add all the numbers together, and all the variables

3y+4(y+2)-36=0

We multiply parentheses

3y+4y+8-36=0

We add all the numbers together, and all the variables

7y-28=0

We move all terms containing y to the left, all other terms to the right

7y=28

y=28/7

y=4

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