4(y+2)+5(3y+1)=

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Solution for 4(y+2)+5(3y+1)= equation:


Simplifying
4(y + 2) + 5(3y + 1) = 0

Reorder the terms:
4(2 + y) + 5(3y + 1) = 0
(2 * 4 + y * 4) + 5(3y + 1) = 0
(8 + 4y) + 5(3y + 1) = 0

Reorder the terms:
8 + 4y + 5(1 + 3y) = 0
8 + 4y + (1 * 5 + 3y * 5) = 0
8 + 4y + (5 + 15y) = 0

Reorder the terms:
8 + 5 + 4y + 15y = 0

Combine like terms: 8 + 5 = 13
13 + 4y + 15y = 0

Combine like terms: 4y + 15y = 19y
13 + 19y = 0

Solving
13 + 19y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 19y = 0 + -13

Combine like terms: 13 + -13 = 0
0 + 19y = 0 + -13
19y = 0 + -13

Combine like terms: 0 + -13 = -13
19y = -13

Divide each side by '19'.
y = -0.6842105263

Simplifying
y = -0.6842105263

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