4(y+2)+7=35

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Solution for 4(y+2)+7=35 equation: 



4(y+2)+7=35

We move all terms to the left:

4(y+2)+7-(35)=0

We add all the numbers together, and all the variables

4(y+2)-28=0

We multiply parentheses

4y+8-28=0

We add all the numbers together, and all the variables

4y-20=0

We move all terms containing y to the left, all other terms to the right

4y=20

y=20/4

y=5

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