4(y+2)-3(1-y)=y+2

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Solution for 4(y+2)-3(1-y)=y+2 equation:


Simplifying
4(y + 2) + -3(1 + -1y) = y + 2

Reorder the terms:
4(2 + y) + -3(1 + -1y) = y + 2
(2 * 4 + y * 4) + -3(1 + -1y) = y + 2
(8 + 4y) + -3(1 + -1y) = y + 2
8 + 4y + (1 * -3 + -1y * -3) = y + 2
8 + 4y + (-3 + 3y) = y + 2

Reorder the terms:
8 + -3 + 4y + 3y = y + 2

Combine like terms: 8 + -3 = 5
5 + 4y + 3y = y + 2

Combine like terms: 4y + 3y = 7y
5 + 7y = y + 2

Reorder the terms:
5 + 7y = 2 + y

Solving
5 + 7y = 2 + y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
5 + 7y + -1y = 2 + y + -1y

Combine like terms: 7y + -1y = 6y
5 + 6y = 2 + y + -1y

Combine like terms: y + -1y = 0
5 + 6y = 2 + 0
5 + 6y = 2

Add '-5' to each side of the equation.
5 + -5 + 6y = 2 + -5

Combine like terms: 5 + -5 = 0
0 + 6y = 2 + -5
6y = 2 + -5

Combine like terms: 2 + -5 = -3
6y = -3

Divide each side by '6'.
y = -0.5

Simplifying
y = -0.5

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