4(y+2)-5(y+1)=y-1

Solution for 4(y+2)-5(y+1)=y-1 equation:

Simplifying
4(y + 2) + -5(y + 1) = y + -1

Reorder the terms:
4(2 + y) + -5(y + 1) = y + -1
(2 * 4 + y * 4) + -5(y + 1) = y + -1
(8 + 4y) + -5(y + 1) = y + -1

Reorder the terms:
8 + 4y + -5(1 + y) = y + -1
8 + 4y + (1 * -5 + y * -5) = y + -1
8 + 4y + (-5 + -5y) = y + -1

Reorder the terms:
8 + -5 + 4y + -5y = y + -1

Combine like terms: 8 + -5 = 3
3 + 4y + -5y = y + -1

Combine like terms: 4y + -5y = -1y
3 + -1y = y + -1

Reorder the terms:
3 + -1y = -1 + y

Solving
3 + -1y = -1 + y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
3 + -1y + -1y = -1 + y + -1y

Combine like terms: -1y + -1y = -2y
3 + -2y = -1 + y + -1y

Combine like terms: y + -1y = 0
3 + -2y = -1 + 0
3 + -2y = -1

Add '-3' to each side of the equation.
3 + -3 + -2y = -1 + -3

Combine like terms: 3 + -3 = 0
0 + -2y = -1 + -3
-2y = -1 + -3

Combine like terms: -1 + -3 = -4
-2y = -4

Divide each side by '-2'.
y = 2

Simplifying
y = 2