4(y+2)-7(2y-1)=30-9(3y-4)

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Solution for 4(y+2)-7(2y-1)=30-9(3y-4) equation: 



4(y+2)-7(2y-1)=30-9(3y-4)

We move all terms to the left:

4(y+2)-7(2y-1)-(30-9(3y-4))=0

We multiply parentheses

4y-14y-(30-9(3y-4))+8+7=0



We calculate terms in parentheses: -(30-9(3y-4)), so:

30-9(3y-4)

determiningTheFunctionDomain
-9(3y-4)+30

We multiply parentheses

-27y+36+30

We add all the numbers together, and all the variables

-27y+66

Back to the equation:

-(-27y+66)



We add all the numbers together, and all the variables

-10y-(-27y+66)+15=0

We get rid of parentheses

-10y+27y-66+15=0

We add all the numbers together, and all the variables

17y-51=0

We move all terms containing y to the left, all other terms to the right

17y=51

y=51/17

y=3

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