4(y+2)-8y=32

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Solution for 4(y+2)-8y=32 equation: 



4(y+2)-8y=32

We move all terms to the left:

4(y+2)-8y-(32)=0

We add all the numbers together, and all the variables

-8y+4(y+2)-32=0

We multiply parentheses

-8y+4y+8-32=0

We add all the numbers together, and all the variables

-4y-24=0

We move all terms containing y to the left, all other terms to the right

-4y=24

y=24/-4

y=-6

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