4(y+2)=-3(y-4)-11

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Solution for 4(y+2)=-3(y-4)-11 equation: 



4(y+2)=-3(y-4)-11

We move all terms to the left:

4(y+2)-(-3(y-4)-11)=0

We multiply parentheses

4y-(-3(y-4)-11)+8=0



We calculate terms in parentheses: -(-3(y-4)-11), so:

-3(y-4)-11

We multiply parentheses

-3y+12-11

We add all the numbers together, and all the variables

-3y+1

Back to the equation:

-(-3y+1)



We get rid of parentheses

4y+3y-1+8=0

We add all the numbers together, and all the variables

7y+7=0

We move all terms containing y to the left, all other terms to the right

7y=-7

y=-7/7

y=-1

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