4(y+2)=-5(3-2y)

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Solution for 4(y+2)=-5(3-2y) equation: 



4(y+2)=-5(3-2y)

We move all terms to the left:

4(y+2)-(-5(3-2y))=0

We add all the numbers together, and all the variables

4(y+2)-(-5(-2y+3))=0

We multiply parentheses

4y-(-5(-2y+3))+8=0



We calculate terms in parentheses: -(-5(-2y+3)), so:

-5(-2y+3)

We multiply parentheses

10y-15

Back to the equation:

-(10y-15)



We get rid of parentheses

4y-10y+15+8=0

We add all the numbers together, and all the variables

-6y+23=0

We move all terms containing y to the left, all other terms to the right

-6y=-23

y=-23/-6

y=3+5/6

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