4(y+2)=3(2y-5)

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Solution for 4(y+2)=3(2y-5) equation: 



4(y+2)=3(2y-5)

We move all terms to the left:

4(y+2)-(3(2y-5))=0

We multiply parentheses

4y-(3(2y-5))+8=0



We calculate terms in parentheses: -(3(2y-5)), so:

3(2y-5)

We multiply parentheses

6y-15

Back to the equation:

-(6y-15)



We get rid of parentheses

4y-6y+15+8=0

We add all the numbers together, and all the variables

-2y+23=0

We move all terms containing y to the left, all other terms to the right

-2y=-23

y=-23/-2

y=11+1/2

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