4(y+2)=3(7y+4)

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Solution for 4(y+2)=3(7y+4) equation: 



4(y+2)=3(7y+4)

We move all terms to the left:

4(y+2)-(3(7y+4))=0

We multiply parentheses

4y-(3(7y+4))+8=0



We calculate terms in parentheses: -(3(7y+4)), so:

3(7y+4)

We multiply parentheses

21y+12

Back to the equation:

-(21y+12)



We get rid of parentheses

4y-21y-12+8=0

We add all the numbers together, and all the variables

-17y-4=0

We move all terms containing y to the left, all other terms to the right

-17y=4

y=4/-17

y=-4/17

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