4(y+2)=40y=8

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Solution for 4(y+2)=40y=8 equation: 



4(y+2)=40y=8

We move all terms to the left:

4(y+2)-(40y)=0

We add all the numbers together, and all the variables

-40y+4(y+2)=0

We multiply parentheses

-40y+4y+8=0

We add all the numbers together, and all the variables

-36y+8=0

We move all terms containing y to the left, all other terms to the right

-36y=-8

y=-8/-36

y=2/9

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