4(y+2)=7(2y-1)

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Solution for 4(y+2)=7(2y-1) equation: 



4(y+2)=7(2y-1)

We move all terms to the left:

4(y+2)-(7(2y-1))=0

We multiply parentheses

4y-(7(2y-1))+8=0



We calculate terms in parentheses: -(7(2y-1)), so:

7(2y-1)

We multiply parentheses

14y-7

Back to the equation:

-(14y-7)



We get rid of parentheses

4y-14y+7+8=0

We add all the numbers together, and all the variables

-10y+15=0

We move all terms containing y to the left, all other terms to the right

-10y=-15

y=-15/-10

y=1+1/2

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