4(y+2)=7+5y

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Solution for 4(y+2)=7+5y equation: 



4(y+2)=7+5y

We move all terms to the left:

4(y+2)-(7+5y)=0

We add all the numbers together, and all the variables

4(y+2)-(5y+7)=0

We multiply parentheses

4y-(5y+7)+8=0

We get rid of parentheses

4y-5y-7+8=0

We add all the numbers together, and all the variables

-1y+1=0

We move all terms containing y to the left, all other terms to the right

-y=-1

y=-1/-1

y=1

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