4(y+2)=8y-12

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Solution for 4(y+2)=8y-12 equation: 



4(y+2)=8y-12

We move all terms to the left:

4(y+2)-(8y-12)=0

We multiply parentheses

4y-(8y-12)+8=0

We get rid of parentheses

4y-8y+12+8=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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