4(y+3)+2y=(9y+6)

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Solution for 4(y+3)+2y=(9y+6) equation: 



4(y+3)+2y=(9y+6)

We move all terms to the left:

4(y+3)+2y-((9y+6))=0

We add all the numbers together, and all the variables

2y+4(y+3)-((9y+6))=0

We multiply parentheses

2y+4y-((9y+6))+12=0



We calculate terms in parentheses: -((9y+6)), so:

(9y+6)

We get rid of parentheses

9y+6

Back to the equation:

-(9y+6)



We add all the numbers together, and all the variables

6y-(9y+6)+12=0

We get rid of parentheses

6y-9y-6+12=0

We add all the numbers together, and all the variables

-3y+6=0

We move all terms containing y to the left, all other terms to the right

-3y=-6

y=-6/-3

y=+2

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