4(y+3)+4=28

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Solution for 4(y+3)+4=28 equation: 



4(y+3)+4=28

We move all terms to the left:

4(y+3)+4-(28)=0

We add all the numbers together, and all the variables

4(y+3)-24=0

We multiply parentheses

4y+12-24=0

We add all the numbers together, and all the variables

4y-12=0

We move all terms containing y to the left, all other terms to the right

4y=12

y=12/4

y=3

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