4(y+3)+7=4y+19

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Solution for 4(y+3)+7=4y+19 equation:


Simplifying
4(y + 3) + 7 = 4y + 19

Reorder the terms:
4(3 + y) + 7 = 4y + 19
(3 * 4 + y * 4) + 7 = 4y + 19
(12 + 4y) + 7 = 4y + 19

Reorder the terms:
12 + 7 + 4y = 4y + 19

Combine like terms: 12 + 7 = 19
19 + 4y = 4y + 19

Reorder the terms:
19 + 4y = 19 + 4y

Add '-19' to each side of the equation.
19 + -19 + 4y = 19 + -19 + 4y

Combine like terms: 19 + -19 = 0
0 + 4y = 19 + -19 + 4y
4y = 19 + -19 + 4y

Combine like terms: 19 + -19 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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