4(y+3)+y=2

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Solution for 4(y+3)+y=2 equation: 



4(y+3)+y=2

We move all terms to the left:

4(y+3)+y-(2)=0

We add all the numbers together, and all the variables

y+4(y+3)-2=0

We multiply parentheses

y+4y+12-2=0

We add all the numbers together, and all the variables

5y+10=0

We move all terms containing y to the left, all other terms to the right

5y=-10

y=-10/5

y=-2

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