4(y+3)-3y=2(y+3)

Solution for 4(y+3)-3y=2(y+3) equation:

4(y+3)-3y=2(y+3)

We move all terms to the left:

4(y+3)-3y-(2(y+3))=0

We add all the numbers together, and all the variables

-3y+4(y+3)-(2(y+3))=0

We multiply parentheses

-3y+4y-(2(y+3))+12=0


We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)


We add all the numbers together, and all the variables

y-(2y+6)+12=0

We get rid of parentheses

y-2y-6+12=0

We add all the numbers together, and all the variables

-1y+6=0

We move all terms containing y to the left, all other terms to the right

-y=-6

y=-6/-1

y=+6