4(y+3)-4(y-1)=6

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Solution for 4(y+3)-4(y-1)=6 equation: 


Simplifying
4(y + 3) + -4(y + -1) = 6

Reorder the terms:
4(3 + y) + -4(y + -1) = 6
(3 * 4 + y * 4) + -4(y + -1) = 6
(12 + 4y) + -4(y + -1) = 6

Reorder the terms:
12 + 4y + -4(-1 + y) = 6
12 + 4y + (-1 * -4 + y * -4) = 6
12 + 4y + (4 + -4y) = 6

Reorder the terms:
12 + 4 + 4y + -4y = 6

Combine like terms: 12 + 4 = 16
16 + 4y + -4y = 6

Combine like terms: 4y + -4y = 0
16 + 0 = 6
16 = 6

Solving
16 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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