4(y+3)-4=8y+10-4y

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Solution for 4(y+3)-4=8y+10-4y equation: 



4(y+3)-4=8y+10-4y

We move all terms to the left:

4(y+3)-4-(8y+10-4y)=0

We add all the numbers together, and all the variables

4(y+3)-(4y+10)-4=0

We multiply parentheses

4y-(4y+10)+12-4=0

We get rid of parentheses

4y-4y-10+12-4=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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