4(y+3)-7y=18

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Solution for 4(y+3)-7y=18 equation:



4(y+3)-7y=18
We move all terms to the left:
4(y+3)-7y-(18)=0
We add all the numbers together, and all the variables
-7y+4(y+3)-18=0
We multiply parentheses
-7y+4y+12-18=0
We add all the numbers together, and all the variables
-3y-6=0
We move all terms containing y to the left, all other terms to the right
-3y=6
y=6/-3
y=-2

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