4(y+3)-y=8(-7-y)

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Solution for 4(y+3)-y=8(-7-y) equation: 



4(y+3)-y=8(-7-y)

We move all terms to the left:

4(y+3)-y-(8(-7-y))=0

We add all the numbers together, and all the variables

4(y+3)-y-(8(-1y-7))=0

We add all the numbers together, and all the variables

-1y+4(y+3)-(8(-1y-7))=0

We multiply parentheses

-1y+4y-(8(-1y-7))+12=0



We calculate terms in parentheses: -(8(-1y-7)), so:

8(-1y-7)

We multiply parentheses

-8y-56

Back to the equation:

-(-8y-56)



We add all the numbers together, and all the variables

3y-(-8y-56)+12=0

We get rid of parentheses

3y+8y+56+12=0

We add all the numbers together, and all the variables

11y+68=0

We move all terms containing y to the left, all other terms to the right

11y=-68

y=-68/11

y=-6+2/11

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