4(y+3)=-20(-3y-6)

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Solution for 4(y+3)=-20(-3y-6) equation:



4(y+3)=-20(-3y-6)
We move all terms to the left:
4(y+3)-(-20(-3y-6))=0
We multiply parentheses
4y-(-20(-3y-6))+12=0
We calculate terms in parentheses: -(-20(-3y-6)), so:
-20(-3y-6)
We multiply parentheses
60y+120
Back to the equation:
-(60y+120)
We get rid of parentheses
4y-60y-120+12=0
We add all the numbers together, and all the variables
-56y-108=0
We move all terms containing y to the left, all other terms to the right
-56y=108
y=108/-56
y=-1+13/14

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