4(y+3)=-3y+40

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Solution for 4(y+3)=-3y+40 equation: 



4(y+3)=-3y+40

We move all terms to the left:

4(y+3)-(-3y+40)=0

We multiply parentheses

4y-(-3y+40)+12=0

We get rid of parentheses

4y+3y-40+12=0

We add all the numbers together, and all the variables

7y-28=0

We move all terms containing y to the left, all other terms to the right

7y=28

y=28/7

y=4

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