4(y+3)=12

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Solution for 4(y+3)=12 equation: 



4(y+3)=12

We move all terms to the left:

4(y+3)-(12)=0

We multiply parentheses

4y+12-12=0

We add all the numbers together, and all the variables

4y=0

y=0/4

y=0

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