4(y+3)=2(6+2y)

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Solution for 4(y+3)=2(6+2y) equation: 



4(y+3)=2(6+2y)

We move all terms to the left:

4(y+3)-(2(6+2y))=0

We add all the numbers together, and all the variables

4(y+3)-(2(2y+6))=0

We multiply parentheses

4y-(2(2y+6))+12=0



We calculate terms in parentheses: -(2(2y+6)), so:

2(2y+6)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We get rid of parentheses

4y-4y-12+12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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