4(y+3)=2(y+6)-8

Solution for 4(y+3)=2(y+6)-8 equation:

4(y+3)=2(y+6)-8

We move all terms to the left:

4(y+3)-(2(y+6)-8)=0

We multiply parentheses

4y-(2(y+6)-8)+12=0


We calculate terms in parentheses: -(2(y+6)-8), so:

2(y+6)-8

We multiply parentheses

2y+12-8

We add all the numbers together, and all the variables

2y+4

Back to the equation:

-(2y+4)


We get rid of parentheses

4y-2y-4+12=0

We add all the numbers together, and all the variables

2y+8=0

We move all terms containing y to the left, all other terms to the right

2y=-8

y=-8/2

y=-4